400-36x^2=0

Solution for 400-36x^2=0 equation:

400-36x^2=0

a = -36; b = 0; c = +400;
Δ = b2-4ac
Δ = 02-4·(-36)·400
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*-36}=\frac{-240}{-72}
=3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*-36}=\frac{240}{-72}
=-3+1/3
$